What is factor 8x^4+28x^3+20x^2 ?

The solution to factor 8x^4+28x^3+20x^2 is 4x^2(x+1)(2x+5)

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factor 8x^4+28x^3+20x^2

factor

8 x^{4} + 28 x^{3} + 20 x^{2}

4 x^{2} (x + 1) (2 x + 5)

Solution steps

8 x^{4} + 28 x^{3} + 20 x^{2}

Factor out common term

4 x^{2} : 4 x^{2} (2 x^{2} + 7 x + 5)

= 4 x^{2} (2 x^{2} + 7 x + 5)

Factor

2 x^{2} + 7 x + 5 : (x + 1) (2 x + 5)

= 4 x^{2} (x + 1) (2 x + 5)

2 (2 + x) - (6 - 7 x) = 133 x - (1 + 4 x)

3^{e} = x

(\frac{- 7 a ^{2} b ^{3} c ^{0}}{3 a ^{3} b ^{4} c ^{3}})^{- 4}

(x + 3) (x - 2) \leq 0

2 x^{2} + 18 = 0

What is factor 8x^4+28x^3+20x^2 ?
The solution to factor 8x^4+28x^3+20x^2 is 4x^2(x+1)(2x+5)