What are the solutions to the equation (x-2)^2=-4 ?

The solutions to the equation (x-2)^2=-4 are x=2i+2,x=-2i+2

Find the zeros of (x-2)^2=-4

The zeros of (x-2)^2=-4 are x=2i+2,x=-2i+2

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(x - 2)^{2} = - 4

x = 2 i + 2, x = - 2 i + 2

Solution steps

(x - 2)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = - 4 : x = 2 i + 2

Solve

x - 2 = - - 4 : x = - 2 i + 2

The solutions to the quadratic equation are:

x = 2 i + 2, x = - 2 i + 2

\frac{3 x ^{5} y}{12 x ^{3} y ^{2}}

1 2^{2} + 1 8^{2} = c^{2}

\frac{d}{7} + 6 = 2

0 + 0

2 x - 6 \geq - 8

What are the solutions to the equation (x-2)^2=-4 ?
The solutions to the equation (x-2)^2=-4 are x=2i+2,x=-2i+2
Find the zeros of (x-2)^2=-4
The zeros of (x-2)^2=-4 are x=2i+2,x=-2i+2