What are the solutions to the equation 12^2+18^2=c^2 ?

The solutions to the equation 12^2+18^2=c^2 are c=6sqrt(13),c=-6sqrt(13)

Find the zeros of 12^2+18^2=c^2

The zeros of 12^2+18^2=c^2 are c=6sqrt(13),c=-6sqrt(13)

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1 2^{2} + 1 8^{2} = c^{2}

c = 613, c = - 613

Decimal Notation

c = 21.63330 \dots, c = - 21.63330 \dots

Solution steps

1 2^{2} + 1 8^{2} = c^{2}

Switch sides

c^{2} = 1 2^{2} + 1 8^{2}

Simplify

1 2^{2} + 1 8^{2} : 468

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 468, c = - 468

468 = 613

- 468 = - 613

c = 613, c = - 613

\frac{d}{7} + 6 = 2

0 + 0

2 x - 6 \geq - 8

\frac{1}{5} \cdot 15

a^{6} - b^{4}

What are the solutions to the equation 12^2+18^2=c^2 ?
The solutions to the equation 12^2+18^2=c^2 are c=6sqrt(13),c=-6sqrt(13)
Find the zeros of 12^2+18^2=c^2
The zeros of 12^2+18^2=c^2 are c=6sqrt(13),c=-6sqrt(13)