What are the solutions to the equation 5(x-4)^2=125 ?

The solutions to the equation 5(x-4)^2=125 are x=9,x=-1

Find the zeros of 5(x-4)^2=125

The zeros of 5(x-4)^2=125 are x=9,x=-1

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5 (x - 4)^{2} = 125

x = 9, x = - 1

Solution steps

5 (x - 4)^{2} = 125

Divide both sides by

5

(x - 4)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 25 : x = 9

Solve

x - 4 = - 25 : x = - 1

The solutions to the quadratic equation are:

x = 9, x = - 1

p^{2} + 8 p + 10 = 0

\frac{1}{3} x = 3

x^{2} y^{4} - x^{5} y^{2}

16 x^{2} + 56 x y + 49 y^{2}

5 (x - 3) = 1 - (x + 4)

What are the solutions to the equation 5(x-4)^2=125 ?
The solutions to the equation 5(x-4)^2=125 are x=9,x=-1
Find the zeros of 5(x-4)^2=125
The zeros of 5(x-4)^2=125 are x=9,x=-1