What are the solutions to the equation x^2-2x+65=0 ?

The solutions to the equation x^2-2x+65=0 are x=1+8i,x=1-8i

Find the zeros of x^2-2x+65=0

The zeros of x^2-2x+65=0 are x=1+8i,x=1-8i

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x^{2} - 2 x + 65 = 0

x = 1 + 8 i, x = 1 - 8 i

Solution steps

x^{2} - 2 x + 65 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 65}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 65 : 16 i

x_{1, 2} = \frac{- ( - 2 ) \pm 16 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 16 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 16 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 16 i}{2 \cdot 1} : 1 + 8 i

x = \frac{- ( - 2 ) - 16 i}{2 \cdot 1} : 1 - 8 i

The solutions to the quadratic equation are:

x = 1 + 8 i, x = 1 - 8 i

3 x^{2} - 10 x - 2 = 0

- 6 (- n - 5) = - 3 (- 4 + 4 n)

(x + 1) (x + 2) = - 3 x - 3

(5 k - 2)^{2} = 64

3 w^{2} - 22 w = 16

What are the solutions to the equation x^2-2x+65=0 ?
The solutions to the equation x^2-2x+65=0 are x=1+8i,x=1-8i
Find the zeros of x^2-2x+65=0
The zeros of x^2-2x+65=0 are x=1+8i,x=1-8i