What are the solutions to the equation 3(x+3)^2-6=0 ?

The solutions to the equation 3(x+3)^2-6=0 are x=sqrt(2)-3,x=-sqrt(2)-3

Find the zeros of 3(x+3)^2-6=0

The zeros of 3(x+3)^2-6=0 are x=sqrt(2)-3,x=-sqrt(2)-3

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3 (x + 3)^{2} - 6 = 0

x = 2 - 3, x = - 2 - 3

Decimal Notation

x = - 1.58578 \dots, x = - 4.41421 \dots

Solution steps

3 (x + 3)^{2} - 6 = 0

Move

6

to the right side

3 (x + 3)^{2} = 6

Divide both sides by

3

(x + 3)^{2} = 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 2 : x = 2 - 3

Solve

x + 3 = - 2 : x = - 2 - 3

The solutions to the quadratic equation are:

x = 2 - 3, x = - 2 - 3

- 3 x^{2} + 9 x - 6 = 0

9 v^{2} - 64 = 0

\frac{9 + m}{3} = 2

(- 3)^{4}

15 x - 10 y

What are the solutions to the equation 3(x+3)^2-6=0 ?
The solutions to the equation 3(x+3)^2-6=0 are x=sqrt(2)-3,x=-sqrt(2)-3
Find the zeros of 3(x+3)^2-6=0
The zeros of 3(x+3)^2-6=0 are x=sqrt(2)-3,x=-sqrt(2)-3