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Popular >

|(x+3)/2 |-2>= 4

Solution

\frac{x + 3}{2} - 2 \geq 4

Solution

x \leq - 15 or x \geq 9

+1

Interval Notation

(- \infty, - 15] \cup [9, \infty)

Solution steps

\frac{x + 3}{2} - 2 \geq 4

Move

2

to the right side

\frac{x + 3}{2} \geq 6

Apply absolute rule: If

∣ u ∣ \geq a, a > 0

then

u \leq - a

or

u \geq a

\frac{x + 3}{2} \leq - 6 or \frac{x + 3}{2} \geq 6

\frac{x + 3}{2} \leq - 6 or \frac{x + 3}{2} \geq 6

x \leq - 15 or x \geq 9

Popular Examples

3/4 (x-1/2)= 9/8

\frac{3}{4} (x - \frac{1}{2}) = \frac{9}{8}

simplify isqrt(6)*isqrt(1/3)simplify

i 6 \cdot i \frac{1}{3}

simplify (6a^5b^{-4})/(a^{-2)b^2}simplify

\frac{6 a ^{5} b ^{- 4}}{a ^{- 2} b ^{2}}

factor 5n^2-5n factor

5 n^{2} - 5 n

-0.1x^2+80x=16000

- 0.1 x^{2} + 80 x = 16000

Frequently Asked Questions (FAQ)

What is |(x+3)/2 |-2>= 4 ?
The solution to |(x+3)/2 |-2>= 4 is x<=-15\lor x>= 9