What are the solutions to the equation -0.1x^2+80x=16000 ?

The solutions to the equation -0.1x^2+80x=16000 are x=400

Find the zeros of -0.1x^2+80x=16000

The zeros of -0.1x^2+80x=16000 are x=400

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- 0.1 x^{2} + 80 x = 16000

x = 400

Solution steps

- 0.1 x^{2} + 80 x = 16000

Multiply both sides by

10

- x^{2} + 800 x = 160000

Move

160000

to the left side

- x^{2} + 800 x - 160000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 800 \pm 80 0 ^{2} - 4 ( - 1 ) ( - 160000 )}{2 ( - 1 )}

80 0^{2} - 4 (- 1) (- 160000) = 0

x_{1, 2} = \frac{- 800 \pm 0}{2 ( - 1 )}

x = \frac{- 800}{2 ( - 1 )}

\frac{- 800}{2 ( - 1 )} = 400

x = 400

The solution to the quadratic equation is:

x = 400

16 b^{4} - 81 d^{4}

x^{4} + 3 x^{3} + 4 x^{2} + 3 x + 1

x^{2} - 11 x = - 30

(x - 1) (x - 1)

12 d^{2} + 4 d - 1

What are the solutions to the equation -0.1x^2+80x=16000 ?
The solutions to the equation -0.1x^2+80x=16000 are x=400
Find the zeros of -0.1x^2+80x=16000
The zeros of -0.1x^2+80x=16000 are x=400