What are the solutions to the equation 8-1/2 (x-4)^2=0 ?

The solutions to the equation 8-1/2 (x-4)^2=0 are x=8,x=0

Find the zeros of 8-1/2 (x-4)^2=0

The zeros of 8-1/2 (x-4)^2=0 are x=8,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8 - \frac{1}{2} (x - 4)^{2} = 0

x = 8, x = 0

Solution steps

8 - \frac{1}{2} (x - 4)^{2} = 0

Move

8

to the right side

- \frac{1}{2} (x - 4)^{2} = - 8

Multiply both sides by

- 2

(x - 4)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 16 : x = 8

Solve

x - 4 = - 16 : x = 0

The solutions to the quadratic equation are:

x = 8, x = 0

x^{2} + 16 x + 44 = 0

\frac{1}{27} = (\frac{1}{3})^{3}

\frac{x ^{2}}{2} + \frac{7}{2} x = 2

\frac{0.6}{6.58 \cdot 1 0 ^{22}}

x^{2} - 6 x = - 13

What are the solutions to the equation 8-1/2 (x-4)^2=0 ?
The solutions to the equation 8-1/2 (x-4)^2=0 are x=8,x=0
Find the zeros of 8-1/2 (x-4)^2=0
The zeros of 8-1/2 (x-4)^2=0 are x=8,x=0