What is |x+1|>= (x-1)/3 ?

The solution to |x+1|>= (x-1)/3 is True for all x

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|x+1|>= (x-1)/3

∣ x + 1 ∣ \geq \frac{x - 1}{3}

True for all x

Interval Notation

(- \infty, \infty)

Solution steps

∣ x + 1 ∣ \geq \frac{x - 1}{3}

Find positive and negative intervals

x < - 1, x \geq - 1

Solve the inequality for each interval

x < - 1 or x \geq - 1

Merge Overlapping Intervals

True for all x

x + 5 = 4

21 \cdot 7

8 c - 7 - (3 c - 11) = 5 (3 c + 11) + 6 c

(\frac{a}{b})^{- 10}

f (x) = x^{2} - 3 x^{2}