What are the solutions to the equation x^2-18x+117=0 ?

The solutions to the equation x^2-18x+117=0 are x=9+6i,x=9-6i

Find the zeros of x^2-18x+117=0

The zeros of x^2-18x+117=0 are x=9+6i,x=9-6i

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x^{2} - 18 x + 117 = 0

x = 9 + 6 i, x = 9 - 6 i

Solution steps

x^{2} - 18 x + 117 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 117}{2 \cdot 1}

Simplify

(- 18)^{2} - 4 \cdot 1 \cdot 117 : 12 i

x_{1, 2} = \frac{- ( - 18 ) \pm 12 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 12 i}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 12 i}{2 \cdot 1}

x = \frac{- ( - 18 ) + 12 i}{2 \cdot 1} : 9 + 6 i

x = \frac{- ( - 18 ) - 12 i}{2 \cdot 1} : 9 - 6 i

The solutions to the quadratic equation are:

x = 9 + 6 i, x = 9 - 6 i

∣ x + 7 ∣ + 25 = 2

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a^{2} + 3 a + 2

3 x^{2} - 15 x + 18

What are the solutions to the equation x^2-18x+117=0 ?
The solutions to the equation x^2-18x+117=0 are x=9+6i,x=9-6i
Find the zeros of x^2-18x+117=0
The zeros of x^2-18x+117=0 are x=9+6i,x=9-6i