What are the solutions to the equation -4x^2+20x-25=0 ?

The solutions to the equation -4x^2+20x-25=0 are x= 5/2

Find the zeros of -4x^2+20x-25=0

The zeros of -4x^2+20x-25=0 are x= 5/2

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- 4 x^{2} + 20 x - 25 = 0

x = \frac{5}{2}

Decimal Notation

x = 2.5

Solution steps

- 4 x^{2} + 20 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 4 ) ( - 25 )}{2 ( - 4 )}

2 0^{2} - 4 (- 4) (- 25) = 0

x_{1, 2} = \frac{- 20 \pm 0}{2 ( - 4 )}

x = \frac{- 20}{2 ( - 4 )}

\frac{- 20}{2 ( - 4 )} = \frac{5}{2}

x = \frac{5}{2}

The solution to the quadratic equation is:

x = \frac{5}{2}

2 x - 3 > \frac{2 x - 5}{2}

x^{2} - 3 x - 4

j^{15} - j^{13}

x - x^{2} + 6 = 0

\frac{3}{2} \cdot \frac{1}{9}

What are the solutions to the equation -4x^2+20x-25=0 ?
The solutions to the equation -4x^2+20x-25=0 are x= 5/2
Find the zeros of -4x^2+20x-25=0
The zeros of -4x^2+20x-25=0 are x= 5/2