What are the solutions to the equation x-x^2+6=0 ?

The solutions to the equation x-x^2+6=0 are x=-2,x=3

Find the zeros of x-x^2+6=0

The zeros of x-x^2+6=0 are x=-2,x=3

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x - x^{2} + 6 = 0

x = - 2, x = 3

Solution steps

x - x^{2} + 6 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 6}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 6 = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 ( - 1 )}, x_{2} = \frac{- 1 - 5}{2 ( - 1 )}

x = \frac{- 1 + 5}{2 ( - 1 )} : - 2

x = \frac{- 1 - 5}{2 ( - 1 )} : 3

The solutions to the quadratic equation are:

x = - 2, x = 3

\frac{3}{2} \cdot \frac{1}{9}

3 ∣ x - 2 ∣ = 18

4 x - 25 = 71

8 x^{2} - 7 x - 5 = 0

- 6 < 2 x + 3 < - 1

What are the solutions to the equation x-x^2+6=0 ?
The solutions to the equation x-x^2+6=0 are x=-2,x=3
Find the zeros of x-x^2+6=0
The zeros of x-x^2+6=0 are x=-2,x=3