What are the solutions to the equation 8x^2-7x-5=0 ?

The solutions to the equation 8x^2-7x-5=0 are x=(7+sqrt(209))/(16),x=(7-sqrt(209))/(16)

Find the zeros of 8x^2-7x-5=0

The zeros of 8x^2-7x-5=0 are x=(7+sqrt(209))/(16),x=(7-sqrt(209))/(16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8 x^{2} - 7 x - 5 = 0

x = \frac{7 + 209}{16}, x = \frac{7 - 209}{16}

Decimal Notation

x = 1.34105 \dots, x = - 0.46605 \dots

Solution steps

8 x^{2} - 7 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 8 ( - 5 )}{2 \cdot 8}

(- 7)^{2} - 4 \cdot 8 (- 5) = 209

x_{1, 2} = \frac{- ( - 7 ) \pm 209}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 209}{2 \cdot 8}, x_{2} = \frac{- ( - 7 ) - 209}{2 \cdot 8}

x = \frac{- ( - 7 ) + 209}{2 \cdot 8} : \frac{7 + 209}{16}

x = \frac{- ( - 7 ) - 209}{2 \cdot 8} : \frac{7 - 209}{16}

The solutions to the quadratic equation are:

x = \frac{7 + 209}{16}, x = \frac{7 - 209}{16}

- 6 < 2 x + 3 < - 1

5 x^{2} + 34 x + 24

(m + a)^{2} - 2 (m + a) (a + b) + (a + b)^{2}

x^{2} - 20 x + 72 = - 3 x

4 (- 1)^{4} - 24 (- 1)^{3} + 14 (- 1)^{2} - 50 (- 1) - 70

What are the solutions to the equation 8x^2-7x-5=0 ?
The solutions to the equation 8x^2-7x-5=0 are x=(7+sqrt(209))/(16),x=(7-sqrt(209))/(16)
Find the zeros of 8x^2-7x-5=0
The zeros of 8x^2-7x-5=0 are x=(7+sqrt(209))/(16),x=(7-sqrt(209))/(16)