m+11<3\lor m/3 >-2

Solution

m + 11 < 3 or \frac{m}{3} > - 2

m < - 8 or m > - 6

Interval Notation

(- \infty, - 8) \cup (- 6, \infty)

Solution steps

m + 11 < 3 or \frac{m}{3} > - 2

m + 11 < 3 : m < - 8

\frac{m}{3} > - 2 : m > - 6

Combine the intervals

m < - 8 or m > - 6

f (1) \frac{( x ^{2} - 2 )}{x ^{2} + x + 1}

(x + 2) (x - 4) + 7 (x - 4)

- 2.17 = 0.35 r

∣ 3 + 4 i ∣

x = 0.5 \cdot (1 - \frac{0.46}{2}) \cdot (1 - 0.46)^{2 - 2}

What is m+11<3\lor m/3 >-2 ?
The solution to m+11<3\lor m/3 >-2 is m<-8\lor m>-6