What are the solutions to the equation 9x^2-63x=0 ?

The solutions to the equation 9x^2-63x=0 are x=7,x=0

Find the zeros of 9x^2-63x=0

The zeros of 9x^2-63x=0 are x=7,x=0

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9 x^{2} - 63 x = 0

x = 7, x = 0

Solution steps

9 x^{2} - 63 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 63 ) \pm ( - 63 ) ^{2} - 4 \cdot 9 \cdot 0}{2 \cdot 9}

(- 63)^{2} - 4 \cdot 9 \cdot 0 = 63

x_{1, 2} = \frac{- ( - 63 ) \pm 63}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 63 ) + 63}{2 \cdot 9}, x_{2} = \frac{- ( - 63 ) - 63}{2 \cdot 9}

x = \frac{- ( - 63 ) + 63}{2 \cdot 9} : 7

x = \frac{- ( - 63 ) - 63}{2 \cdot 9} : 0

The solutions to the quadratic equation are:

x = 7, x = 0

3 x^{2} + 4 x + x

(x - 2) (x - 1) = 2

x y - 7 x + 7 y - 49

- 2 x - 5 \leq 3 x - 5

(5 x - 2)^{2} = 10

What are the solutions to the equation 9x^2-63x=0 ?
The solutions to the equation 9x^2-63x=0 are x=7,x=0
Find the zeros of 9x^2-63x=0
The zeros of 9x^2-63x=0 are x=7,x=0