What are the solutions to the equation (x-2)(x-1)=2 ?

The solutions to the equation (x-2)(x-1)=2 are x=3,x=0

Find the zeros of (x-2)(x-1)=2

The zeros of (x-2)(x-1)=2 are x=3,x=0

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(x - 2) (x - 1) = 2

x = 3, x = 0

Solution steps

(x - 2) (x - 1) = 2

Expand

(x - 2) (x - 1) : x^{2} - 3 x + 2

x^{2} - 3 x + 2 = 2

Move

2

to the left side

x^{2} - 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 0 = 3

x_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 1}

x = \frac{- ( - 3 ) + 3}{2 \cdot 1} : 3

x = \frac{- ( - 3 ) - 3}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 3, x = 0

x y - 7 x + 7 y - 49

- 2 x - 5 \leq 3 x - 5

(5 x - 2)^{2} = 10

x^{2} + 45 x = - 200

- \frac{x}{11} - 2 + 5 > 9

What are the solutions to the equation (x-2)(x-1)=2 ?
The solutions to the equation (x-2)(x-1)=2 are x=3,x=0
Find the zeros of (x-2)(x-1)=2
The zeros of (x-2)(x-1)=2 are x=3,x=0