What are the solutions to the equation 2x^2-3x=2 ?

The solutions to the equation 2x^2-3x=2 are x=2,x=-1/2

Find the zeros of 2x^2-3x=2

The zeros of 2x^2-3x=2 are x=2,x=-1/2

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2 x^{2} - 3 x = 2

x = 2, x = - \frac{1}{2}

Decimal Notation

x = 2, x = - 0.5

Solution steps

2 x^{2} - 3 x = 2

Move

2

to the left side

2 x^{2} - 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 2) = 5

x_{1, 2} = \frac{- ( - 3 ) \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 5}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 5}{2 \cdot 2}

x = \frac{- ( - 3 ) + 5}{2 \cdot 2} : 2

x = \frac{- ( - 3 ) - 5}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{1}{2}

\frac{32}{5}

\frac{147}{4} - x = 5

- 2 x^{2} - 24 x - 322 = 0

49 x^{4} - 4 (x^{2} - 3 x)^{2}

x - \frac{2 x - 1}{2} - \frac{2 x - 17}{16} = 1

What are the solutions to the equation 2x^2-3x=2 ?
The solutions to the equation 2x^2-3x=2 are x=2,x=-1/2
Find the zeros of 2x^2-3x=2
The zeros of 2x^2-3x=2 are x=2,x=-1/2