What are the solutions to the equation -2x^2-24x-322=0 ?

The solutions to the equation -2x^2-24x-322=0 are x=-6-5sqrt(5)i,x=-6+5sqrt(5)i

Find the zeros of -2x^2-24x-322=0

The zeros of -2x^2-24x-322=0 are x=-6-5sqrt(5)i,x=-6+5sqrt(5)i

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- 2 x^{2} - 24 x - 322 = 0

x = - 6 - 55 i, x = - 6 + 55 i

Solution steps

- 2 x^{2} - 24 x - 322 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 ( - 2 ) ( - 322 )}{2 ( - 2 )}

Simplify

(- 24)^{2} - 4 (- 2) (- 322) : 205 i

x_{1, 2} = \frac{- ( - 24 ) \pm 20 5 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 20 5 i}{2 ( - 2 )}, x_{2} = \frac{- ( - 24 ) - 20 5 i}{2 ( - 2 )}

x = \frac{- ( - 24 ) + 20 5 i}{2 ( - 2 )} : - 6 - 55 i

x = \frac{- ( - 24 ) - 20 5 i}{2 ( - 2 )} : - 6 + 55 i

The solutions to the quadratic equation are:

x = - 6 - 55 i, x = - 6 + 55 i

49 x^{4} - 4 (x^{2} - 3 x)^{2}

x - \frac{2 x - 1}{2} - \frac{2 x - 17}{16} = 1

2 x^{2} + 4 x - 2 = 0

\frac{12 x}{6 x y}

- 2 < 2 - 2 x \leq 12

What are the solutions to the equation -2x^2-24x-322=0 ?
The solutions to the equation -2x^2-24x-322=0 are x=-6-5sqrt(5)i,x=-6+5sqrt(5)i
Find the zeros of -2x^2-24x-322=0
The zeros of -2x^2-24x-322=0 are x=-6-5sqrt(5)i,x=-6+5sqrt(5)i