What are the solutions to the equation 2x^2+4x-2=0 ?

The solutions to the equation 2x^2+4x-2=0 are x=-1+sqrt(2),x=-1-sqrt(2)

Find the zeros of 2x^2+4x-2=0

The zeros of 2x^2+4x-2=0 are x=-1+sqrt(2),x=-1-sqrt(2)

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2 x^{2} + 4 x - 2 = 0

x = - 1 + 2, x = - 1 - 2

Decimal Notation

x = 0.41421 \dots, x = - 2.41421 \dots

Solution steps

2 x^{2} + 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 2) = 42

x_{1, 2} = \frac{- 4 \pm 4 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 4 2}{2 \cdot 2}, x_{2} = \frac{- 4 - 4 2}{2 \cdot 2}

x = \frac{- 4 + 4 2}{2 \cdot 2} : - 1 + 2

x = \frac{- 4 - 4 2}{2 \cdot 2} : - 1 - 2

The solutions to the quadratic equation are:

x = - 1 + 2, x = - 1 - 2

\frac{12 x}{6 x y}

- 2 < 2 - 2 x \leq 12

s^{2} - 4 s = 0

s^{2} + 3 s + 2 > 0

3 x^{5} + 18 x^{4} + 27 x^{3} - 12 x^{2} - 36 x

What are the solutions to the equation 2x^2+4x-2=0 ?
The solutions to the equation 2x^2+4x-2=0 are x=-1+sqrt(2),x=-1-sqrt(2)
Find the zeros of 2x^2+4x-2=0
The zeros of 2x^2+4x-2=0 are x=-1+sqrt(2),x=-1-sqrt(2)