What are the solutions to the equation s^2-4s=0 ?

The solutions to the equation s^2-4s=0 are s=4,s=0

Find the zeros of s^2-4s=0

The zeros of s^2-4s=0 are s=4,s=0

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s^{2} - 4 s = 0

s = 4, s = 0

Solution steps

s^{2} - 4 s = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

s_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, s_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

s = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

s = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

s = 4, s = 0

s^{2} + 3 s + 2 > 0

3 x^{5} + 18 x^{4} + 27 x^{3} - 12 x^{2} - 36 x

(5 x^{5}) (3 y^{6}) (3 x^{2})

5 x - 3 = - 13

0 = 2 x^{2} + 26 x + 72

What are the solutions to the equation s^2-4s=0 ?
The solutions to the equation s^2-4s=0 are s=4,s=0
Find the zeros of s^2-4s=0
The zeros of s^2-4s=0 are s=4,s=0