What are the solutions to the equation 0=2x^2+26x+72 ?

The solutions to the equation 0=2x^2+26x+72 are x=-4,x=-9

Find the zeros of 0=2x^2+26x+72

The zeros of 0=2x^2+26x+72 are x=-4,x=-9

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0 = 2 x^{2} + 26 x + 72

x = - 4, x = - 9

Solution steps

0 = 2 x^{2} + 26 x + 72

Switch sides

2 x^{2} + 26 x + 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 \cdot 2 \cdot 72}{2 \cdot 2}

2 6^{2} - 4 \cdot 2 \cdot 72 = 10

x_{1, 2} = \frac{- 26 \pm 10}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 26 + 10}{2 \cdot 2}, x_{2} = \frac{- 26 - 10}{2 \cdot 2}

x = \frac{- 26 + 10}{2 \cdot 2} : - 4

x = \frac{- 26 - 10}{2 \cdot 2} : - 9

The solutions to the quadratic equation are:

x = - 4, x = - 9

\frac{2}{3} x - 4 = - \frac{2}{3} x + 8

\frac{6}{- 16}

\frac{1}{2} x = 12

2 x^{2} - x = - 2

\frac{x}{4} - \frac{1}{4} \leq \frac{x}{5} + 1

What are the solutions to the equation 0=2x^2+26x+72 ?
The solutions to the equation 0=2x^2+26x+72 are x=-4,x=-9
Find the zeros of 0=2x^2+26x+72
The zeros of 0=2x^2+26x+72 are x=-4,x=-9