What are the solutions to the equation -2x^2+3x+7=0 ?

The solutions to the equation -2x^2+3x+7=0 are x=-(-3+sqrt(65))/4 ,x=(3+sqrt(65))/4

Find the zeros of -2x^2+3x+7=0

The zeros of -2x^2+3x+7=0 are x=-(-3+sqrt(65))/4 ,x=(3+sqrt(65))/4

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- 2 x^{2} + 3 x + 7 = 0

x = - \frac{- 3 + 65}{4}, x = \frac{3 + 65}{4}

Decimal Notation

x = - 1.26556 \dots, x = 2.76556 \dots

Solution steps

- 2 x^{2} + 3 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 2 ) \cdot 7}{2 ( - 2 )}

3^{2} - 4 (- 2) \cdot 7 = 65

x_{1, 2} = \frac{- 3 \pm 65}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 3 + 65}{2 ( - 2 )}, x_{2} = \frac{- 3 - 65}{2 ( - 2 )}

x = \frac{- 3 + 65}{2 ( - 2 )} : - \frac{- 3 + 65}{4}

x = \frac{- 3 - 65}{2 ( - 2 )} : \frac{3 + 65}{4}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 65}{4}, x = \frac{3 + 65}{4}

(\frac{8}{10})^{2}

\frac{4 - a}{5 a} \cdot \frac{a ^{2} + 5 a}{a ^{2} + a - 20}

2 n^{2} - n - 4 = 2

\frac{3}{7} = \frac{9}{28}

1.49 m \leq 8.94

What are the solutions to the equation -2x^2+3x+7=0 ?
The solutions to the equation -2x^2+3x+7=0 are x=-(-3+sqrt(65))/4 ,x=(3+sqrt(65))/4
Find the zeros of -2x^2+3x+7=0
The zeros of -2x^2+3x+7=0 are x=-(-3+sqrt(65))/4 ,x=(3+sqrt(65))/4