What are the solutions to the equation 7x^2+x=4x^2-x+1 ?

The solutions to the equation 7x^2+x=4x^2-x+1 are x=-1,x= 1/3

Find the zeros of 7x^2+x=4x^2-x+1

The zeros of 7x^2+x=4x^2-x+1 are x=-1,x= 1/3

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7 x^{2} + x = 4 x^{2} - x + 1

x = - 1, x = \frac{1}{3}

Decimal Notation

x = - 1, x = 0.33333 \dots

Solution steps

7 x^{2} + x = 4 x^{2} - x + 1

Switch sides

4 x^{2} - x + 1 = 7 x^{2} + x

Move

x

to the left side

4 x^{2} - 2 x + 1 = 7 x^{2}

Move

7 x^{2}

to the left side

- 3 x^{2} - 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 3 ) \cdot 1}{2 ( - 3 )}

(- 2)^{2} - 4 (- 3) \cdot 1 = 4

x_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4}{2 ( - 3 )}, x_{2} = \frac{- ( - 2 ) - 4}{2 ( - 3 )}

x = \frac{- ( - 2 ) + 4}{2 ( - 3 )} : - 1

x = \frac{- ( - 2 ) - 4}{2 ( - 3 )} : \frac{1}{3}

The solutions to the quadratic equation are:

x = - 1, x = \frac{1}{3}

10 x^{2} - 19 x + 6

\frac{x}{8} = \frac{6}{4}

3 - y = 2

a^{2} + a + a^{2} = 1

2 x^{2} - 72

What are the solutions to the equation 7x^2+x=4x^2-x+1 ?
The solutions to the equation 7x^2+x=4x^2-x+1 are x=-1,x= 1/3
Find the zeros of 7x^2+x=4x^2-x+1
The zeros of 7x^2+x=4x^2-x+1 are x=-1,x= 1/3