What are the solutions to the equation 11x^2-6x-2=0 ?

The solutions to the equation 11x^2-6x-2=0 are x=(3+sqrt(31))/(11),x=(3-sqrt(31))/(11)

Find the zeros of 11x^2-6x-2=0

The zeros of 11x^2-6x-2=0 are x=(3+sqrt(31))/(11),x=(3-sqrt(31))/(11)

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11 x^{2} - 6 x - 2 = 0

x = \frac{3 + 31}{11}, x = \frac{3 - 31}{11}

Decimal Notation

x = 0.77888 \dots, x = - 0.23343 \dots

Solution steps

11 x^{2} - 6 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 11 ( - 2 )}{2 \cdot 11}

(- 6)^{2} - 4 \cdot 11 (- 2) = 231

x_{1, 2} = \frac{- ( - 6 ) \pm 2 31}{2 \cdot 11}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 31}{2 \cdot 11}, x_{2} = \frac{- ( - 6 ) - 2 31}{2 \cdot 11}

x = \frac{- ( - 6 ) + 2 31}{2 \cdot 11} : \frac{3 + 31}{11}

x = \frac{- ( - 6 ) - 2 31}{2 \cdot 11} : \frac{3 - 31}{11}

The solutions to the quadratic equation are:

x = \frac{3 + 31}{11}, x = \frac{3 - 31}{11}

∣ 2 x - 2 ∣ = ∣ - 8 ∣

\frac{3 x + 7}{2} + \frac{x - 7}{3} = \frac{17}{2}

x^{3} + 7 x^{2} + 10 x \geq 0

5 x = x + 20

4 n^{2} - 176

What are the solutions to the equation 11x^2-6x-2=0 ?
The solutions to the equation 11x^2-6x-2=0 are x=(3+sqrt(31))/(11),x=(3-sqrt(31))/(11)
Find the zeros of 11x^2-6x-2=0
The zeros of 11x^2-6x-2=0 are x=(3+sqrt(31))/(11),x=(3-sqrt(31))/(11)