What are the solutions to the equation (x-2)^2-10(x-2)=-9 ?

The solutions to the equation (x-2)^2-10(x-2)=-9 are x=11,x=3

Find the zeros of (x-2)^2-10(x-2)=-9

The zeros of (x-2)^2-10(x-2)=-9 are x=11,x=3

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(x - 2)^{2} - 10 (x - 2) = - 9

x = 11, x = 3

Solution steps

(x - 2)^{2} - 10 (x - 2) = - 9

Expand

(x - 2)^{2} - 10 (x - 2) : x^{2} - 14 x + 24

x^{2} - 14 x + 24 = - 9

Move

9

to the left side

x^{2} - 14 x + 33 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 33}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 33 = 8

x_{1, 2} = \frac{- ( - 14 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 8}{2 \cdot 1}

x = \frac{- ( - 14 ) + 8}{2 \cdot 1} : 11

x = \frac{- ( - 14 ) - 8}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 11, x = 3

2 x - 3 x - 3 x - x = 24 - 5 + 2

\frac{- 2 + 3 i}{1 - 8 i}

- 73 \geq 15 + 11 x

\frac{2 x - 1}{2 x + 1} \leq \frac{x + 1}{x - 1}

- 2 x^{2} + 8 x < 0

What are the solutions to the equation (x-2)^2-10(x-2)=-9 ?
The solutions to the equation (x-2)^2-10(x-2)=-9 are x=11,x=3
Find the zeros of (x-2)^2-10(x-2)=-9
The zeros of (x-2)^2-10(x-2)=-9 are x=11,x=3