What are the solutions to the equation x^2-9x+25=0 ?

The solutions to the equation x^2-9x+25=0 are x= 9/2+i(sqrt(19))/2 ,x= 9/2-i(sqrt(19))/2

Find the zeros of x^2-9x+25=0

The zeros of x^2-9x+25=0 are x= 9/2+i(sqrt(19))/2 ,x= 9/2-i(sqrt(19))/2

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x^{2} - 9 x + 25 = 0

x = \frac{9}{2} + i \frac{19}{2}, x = \frac{9}{2} - i \frac{19}{2}

Solution steps

x^{2} - 9 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

(- 9)^{2} - 4 \cdot 1 \cdot 25 : 19 i

x_{1, 2} = \frac{- ( - 9 ) \pm 19 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 19 i}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 19 i}{2 \cdot 1}

x = \frac{- ( - 9 ) + 19 i}{2 \cdot 1} : \frac{9}{2} + i \frac{19}{2}

x = \frac{- ( - 9 ) - 19 i}{2 \cdot 1} : \frac{9}{2} - i \frac{19}{2}

The solutions to the quadratic equation are:

x = \frac{9}{2} + i \frac{19}{2}, x = \frac{9}{2} - i \frac{19}{2}

2 x^{2} + 8 x + 2 = 0

- 12 v - 9 + 7 v = 26

6 (x - 1) > 18

7 x - 3 = - 10

3 + 5 x \geq 18

What are the solutions to the equation x^2-9x+25=0 ?
The solutions to the equation x^2-9x+25=0 are x= 9/2+i(sqrt(19))/2 ,x= 9/2-i(sqrt(19))/2
Find the zeros of x^2-9x+25=0
The zeros of x^2-9x+25=0 are x= 9/2+i(sqrt(19))/2 ,x= 9/2-i(sqrt(19))/2