What are the solutions to the equation 0=80t-16t^2 ?

The solutions to the equation 0=80t-16t^2 are t=0,t=5

Find the zeros of 0=80t-16t^2

The zeros of 0=80t-16t^2 are t=0,t=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = 80 t - 16 t^{2}

t = 0, t = 5

Solution steps

0 = 80 t - 16 t^{2}

Switch sides

80 t - 16 t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 t^{2} + 80 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

8 0^{2} - 4 (- 16) \cdot 0 = 80

t_{1, 2} = \frac{- 80 \pm 80}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 80 + 80}{2 ( - 16 )}, t_{2} = \frac{- 80 - 80}{2 ( - 16 )}

t = \frac{- 80 + 80}{2 ( - 16 )} : 0

t = \frac{- 80 - 80}{2 ( - 16 )} : 5

The solutions to the quadratic equation are:

t = 0, t = 5

(2 + 3 i) (\frac{2 - i}{1 + 2 i})^{2}

6 - 3 i

x = lo g_{3} (\frac{1}{9})

8 (8)^{\frac{1}{3}} - 5

\frac{x}{2} + \frac{x}{3} = \frac{5 x + 2}{6}

What are the solutions to the equation 0=80t-16t^2 ?
The solutions to the equation 0=80t-16t^2 are t=0,t=5
Find the zeros of 0=80t-16t^2
The zeros of 0=80t-16t^2 are t=0,t=5