What is (2+3i)((2-i)/(1+2i))^2 ?

The solution to (2+3i)((2-i)/(1+2i))^2 is -2-3i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (2+3i)((2-i)/(1+2i))^2

simplify

(2 + 3 i) (\frac{2 - i}{1 + 2 i})^{2}

- 2 - 3 i

Solution steps

(2 + 3 i) (\frac{2 - i}{1 + 2 i})^{2}

(\frac{2 - i}{1 + 2 i})^{2} = i^{2}

= i^{2} (2 + 3 i)

i^{2} = - 1

= (- 1) (2 + 3 i)

Remove parentheses:

(- a) = - a

= - (2 + 3 i) \cdot 1

Multiply:

(2 + 3 i) \cdot 1 = (2 + 3 i)

= - (2 + 3 i)

Distribute parentheses

= - (2) - (3 i)

Apply minus-plus rules

+ (- a) = - a

= - 2 - 3 i

6 - 3 i

x = lo g_{3} (\frac{1}{9})

8 (8)^{\frac{1}{3}} - 5

\frac{x}{2} + \frac{x}{3} = \frac{5 x + 2}{6}

\frac{1}{3} (y + 4) + 6 = \frac{1}{4} (3 y - 1) - 2

What is (2+3i)((2-i)/(1+2i))^2 ?
The solution to (2+3i)((2-i)/(1+2i))^2 is -2-3i