What are the solutions to the equation 12^2+b^2=17^2 ?

The solutions to the equation 12^2+b^2=17^2 are b=sqrt(145),b=-sqrt(145)

Find the zeros of 12^2+b^2=17^2

The zeros of 12^2+b^2=17^2 are b=sqrt(145),b=-sqrt(145)

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1 2^{2} + b^{2} = 1 7^{2}

b = 145, b = - 145

Decimal Notation

b = 12.04159 \dots, b = - 12.04159 \dots

Solution steps

1 2^{2} + b^{2} = 1 7^{2}

Move

1 2^{2}

to the right side

b^{2} = 145

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 145, b = - 145

2 x = 3 x - 3

k - 16 = - 28

\frac{π}{\frac{2}{2 π}}

(\frac{3}{5})^{3} \cdot (\frac{2}{7})^{3}

\frac{180}{5}

What are the solutions to the equation 12^2+b^2=17^2 ?
The solutions to the equation 12^2+b^2=17^2 are b=sqrt(145),b=-sqrt(145)
Find the zeros of 12^2+b^2=17^2
The zeros of 12^2+b^2=17^2 are b=sqrt(145),b=-sqrt(145)