What are the solutions to the equation h^2-30h-120=0 ?

The solutions to the equation h^2-30h-120=0 are h=15+sqrt(345),h=15-sqrt(345)

Find the zeros of h^2-30h-120=0

The zeros of h^2-30h-120=0 are h=15+sqrt(345),h=15-sqrt(345)

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h^{2} - 30 h - 120 = 0

h = 15 + 345, h = 15 - 345

Decimal Notation

h = 33.57417 \dots, h = - 3.57417 \dots

Solution steps

h^{2} - 30 h - 120 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 1 \cdot ( - 120 )}{2 \cdot 1}

(- 30)^{2} - 4 \cdot 1 \cdot (- 120) = 2345

h_{1, 2} = \frac{- ( - 30 ) \pm 2 345}{2 \cdot 1}

Separate the solutions

h_{1} = \frac{- ( - 30 ) + 2 345}{2 \cdot 1}, h_{2} = \frac{- ( - 30 ) - 2 345}{2 \cdot 1}

h = \frac{- ( - 30 ) + 2 345}{2 \cdot 1} : 15 + 345

h = \frac{- ( - 30 ) - 2 345}{2 \cdot 1} : 15 - 345

The solutions to the quadratic equation are:

h = 15 + 345, h = 15 - 345

1 > 0

18 + 4 y = 26

v^{2} - 5 v = 0

3 x^{2} + 8 x - 11

(\frac{1}{8})^{0}

What are the solutions to the equation h^2-30h-120=0 ?
The solutions to the equation h^2-30h-120=0 are h=15+sqrt(345),h=15-sqrt(345)
Find the zeros of h^2-30h-120=0
The zeros of h^2-30h-120=0 are h=15+sqrt(345),h=15-sqrt(345)