What are the solutions to the equation 6x^2+24x-413=0 ?

The solutions to the equation 6x^2+24x-413=0 are x=(-12+sqrt(2622))/6 ,x=-(12+sqrt(2622))/6

Find the zeros of 6x^2+24x-413=0

The zeros of 6x^2+24x-413=0 are x=(-12+sqrt(2622))/6 ,x=-(12+sqrt(2622))/6

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6 x^{2} + 24 x - 413 = 0

x = \frac{- 12 + 2622}{6}, x = - \frac{12 + 2622}{6}

Decimal Notation

x = 6.53424 \dots, x = - 10.53424 \dots

Solution steps

6 x^{2} + 24 x - 413 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 6 ( - 413 )}{2 \cdot 6}

2 4^{2} - 4 \cdot 6 (- 413) = 22622

x_{1, 2} = \frac{- 24 \pm 2 2622}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 24 + 2 2622}{2 \cdot 6}, x_{2} = \frac{- 24 - 2 2622}{2 \cdot 6}

x = \frac{- 24 + 2 2622}{2 \cdot 6} : \frac{- 12 + 2622}{6}

x = \frac{- 24 - 2 2622}{2 \cdot 6} : - \frac{12 + 2622}{6}

The solutions to the quadratic equation are:

x = \frac{- 12 + 2622}{6}, x = - \frac{12 + 2622}{6}

- 3 x - 1 > 5

(x - 1)^{2} (8 - 2 x) > 0

(\frac{7}{9} \cdot \frac{5}{3} + \frac{2}{4} - \frac{1}{4}) \div \frac{6}{9}

\frac{1 + i}{7 + 7 i}

3 y + 4 = 22

What are the solutions to the equation 6x^2+24x-413=0 ?
The solutions to the equation 6x^2+24x-413=0 are x=(-12+sqrt(2622))/6 ,x=-(12+sqrt(2622))/6
Find the zeros of 6x^2+24x-413=0
The zeros of 6x^2+24x-413=0 are x=(-12+sqrt(2622))/6 ,x=-(12+sqrt(2622))/6