What are the solutions to the equation x^2-10x+25=4 ?

The solutions to the equation x^2-10x+25=4 are x=7,x=3

Find the zeros of x^2-10x+25=4

The zeros of x^2-10x+25=4 are x=7,x=3

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x^{2} - 10 x + 25 = 4

x = 7, x = 3

Solution steps

x^{2} - 10 x + 25 = 4

Move

4

to the left side

x^{2} - 10 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 21 = 4

x_{1, 2} = \frac{- ( - 10 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 4}{2 \cdot 1}

x = \frac{- ( - 10 ) + 4}{2 \cdot 1} : 7

x = \frac{- ( - 10 ) - 4}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 7, x = 3

3 x + 4 = x + 10

2 x^{2} - 7 x = 1

- x^{2} - 10 x - 26 \leq - 5

\frac{4 a b ^{- 2}}{- 3 c ^{- 2}}

\frac{( x + 3 ) ( x - 3 ) - 4}{2} - \frac{x - 2}{3} = \frac{( x - 2 ) ^{2} + 1}{6}

What are the solutions to the equation x^2-10x+25=4 ?
The solutions to the equation x^2-10x+25=4 are x=7,x=3
Find the zeros of x^2-10x+25=4
The zeros of x^2-10x+25=4 are x=7,x=3