What are the solutions to the equation 4x^2-16x+7=0 ?

The solutions to the equation 4x^2-16x+7=0 are x= 7/2 ,x= 1/2

Find the zeros of 4x^2-16x+7=0

The zeros of 4x^2-16x+7=0 are x= 7/2 ,x= 1/2

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4 x^{2} - 16 x + 7 = 0

x = \frac{7}{2}, x = \frac{1}{2}

Decimal Notation

x = 3.5, x = 0.5

Solution steps

4 x^{2} - 16 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 4 \cdot 7}{2 \cdot 4}

(- 16)^{2} - 4 \cdot 4 \cdot 7 = 12

x_{1, 2} = \frac{- ( - 16 ) \pm 12}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 12}{2 \cdot 4}, x_{2} = \frac{- ( - 16 ) - 12}{2 \cdot 4}

x = \frac{- ( - 16 ) + 12}{2 \cdot 4} : \frac{7}{2}

x = \frac{- ( - 16 ) - 12}{2 \cdot 4} : \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = \frac{1}{2}

5 x^{2} + 3 x + 5 = 0

5 x^{2} + 10 x

1 - a^{2}

s^{2} - 7 s + 12 = 0

5 x + 11 < 26

What are the solutions to the equation 4x^2-16x+7=0 ?
The solutions to the equation 4x^2-16x+7=0 are x= 7/2 ,x= 1/2
Find the zeros of 4x^2-16x+7=0
The zeros of 4x^2-16x+7=0 are x= 7/2 ,x= 1/2