What are the solutions to the equation m^2+2m+m=0 ?

The solutions to the equation m^2+2m+m=0 are m=0,m=-3

Find the zeros of m^2+2m+m=0

The zeros of m^2+2m+m=0 are m=0,m=-3

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m^{2} + 2 m + m = 0

m = 0, m = - 3

Solution steps

m^{2} + 2 m + m = 0

Refine

m^{2} + 3 m = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 0 = 3

m_{1, 2} = \frac{- 3 \pm 3}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 3 + 3}{2 \cdot 1}, m_{2} = \frac{- 3 - 3}{2 \cdot 1}

m = \frac{- 3 + 3}{2 \cdot 1} : 0

m = \frac{- 3 - 3}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

m = 0, m = - 3

(5^{2})^{- 8}

1.6 k = 3.2

2 x^{2} - 34 x + 104 = 0

2 x^{2} + 6 x - 31 = 0

32 = 704 + 16 t - 16 t^{2}

What are the solutions to the equation m^2+2m+m=0 ?
The solutions to the equation m^2+2m+m=0 are m=0,m=-3
Find the zeros of m^2+2m+m=0
The zeros of m^2+2m+m=0 are m=0,m=-3