What are the solutions to the equation x=2x(1-x) ?

The solutions to the equation x=2x(1-x) are x=0,x= 1/2

Find the zeros of x=2x(1-x)

The zeros of x=2x(1-x) are x=0,x= 1/2

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x = 2 x (1 - x)

x = 0, x = \frac{1}{2}

Decimal Notation

x = 0, x = 0.5

Solution steps

x = 2 x (1 - x)

Expand

2 x (1 - x) : 2 x - 2 x^{2}

x = 2 x - 2 x^{2}

Switch sides

2 x - 2 x^{2} = x

Move

x

to the left side

- 2 x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

1^{2} - 4 (- 2) \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 ( - 2 )}, x_{2} = \frac{- 1 - 1}{2 ( - 2 )}

x = \frac{- 1 + 1}{2 ( - 2 )} : 0

x = \frac{- 1 - 1}{2 ( - 2 )} : \frac{1}{2}

The solutions to the quadratic equation are:

x = 0, x = \frac{1}{2}

(x - 3) (2 x + 1) = 0

∣ x - 1 ∣ + ∣ x + 3 ∣ = 4

7 f - 3 \leq 4 f + 6

(- 27)^{\frac{1}{3}}

16 - 7

What are the solutions to the equation x=2x(1-x) ?
The solutions to the equation x=2x(1-x) are x=0,x= 1/2
Find the zeros of x=2x(1-x)
The zeros of x=2x(1-x) are x=0,x= 1/2