What is factor y^8-1 ?

The solution to factor y^8-1 is (y^4+1)(y^2+1)(y+1)(y-1)

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factor y^8-1

factor

y^{8} - 1

(y^{4} + 1) (y^{2} + 1) (y + 1) (y - 1)

Solution steps

y^{8} - 1

Apply exponent rules

= (y^{4})^{2} - 1^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(y^{4})^{2} - 1^{2} = (y^{4} + 1) (y^{4} - 1)

= (y^{4} + 1) (y^{4} - 1)

Factor

y^{4} - 1 : (y^{2} + 1) (y + 1) (y - 1)

= (y^{4} + 1) (y^{2} + 1) (y + 1) (y - 1)

4 x^{2} + 9 = 15

49 x^{2} - 70 x + 25

3 x^{2} + 18 x + 27

x \geq 2 and x \leq 8

\frac{( 2 + 5 i )}{( 3 - 2 i )}