What are the solutions to the equation (2x-3)^2=1 ?

The solutions to the equation (2x-3)^2=1 are x=2,x=1

Find the zeros of (2x-3)^2=1

The zeros of (2x-3)^2=1 are x=2,x=1

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(2 x - 3)^{2} = 1

x = 2, x = 1

Solution steps

(2 x - 3)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 3 = 1 : x = 2

Solve

2 x - 3 = - 1 : x = 1

The solutions to the quadratic equation are:

x = 2, x = 1

2 x^{2} + 13 x - 99 = 0

\frac{( - 3 ) ^{0}}{( - 3 ) ^{2}}

\frac{4}{6} \cdot \frac{3}{8}

x^{3} - 2 x^{2}

- 13 \geq \frac{1}{4} r - 16

What are the solutions to the equation (2x-3)^2=1 ?
The solutions to the equation (2x-3)^2=1 are x=2,x=1
Find the zeros of (2x-3)^2=1
The zeros of (2x-3)^2=1 are x=2,x=1