What are the solutions to the equation a^2-4a=0 ?

The solutions to the equation a^2-4a=0 are a=4,a=0

Find the zeros of a^2-4a=0

The zeros of a^2-4a=0 are a=4,a=0

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a^{2} - 4 a = 0

a = 4, a = 0

Solution steps

a^{2} - 4 a = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

a_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, a_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

a = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

a = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

a = 4, a = 0

x^{2} - (\frac{x}{2})^{2} = 3

15 x^{2} + 34 x + 15

10 x^{2} + 17 x + 3 = 0

x^{2} + 6 x + 10 = 0

\frac{3 x}{2} - \frac{4 x}{5} + \frac{x}{6} = 0

What are the solutions to the equation a^2-4a=0 ?
The solutions to the equation a^2-4a=0 are a=4,a=0
Find the zeros of a^2-4a=0
The zeros of a^2-4a=0 are a=4,a=0