What are the solutions to the equation 3x^2-9x+2=0 ?

The solutions to the equation 3x^2-9x+2=0 are x=(9+sqrt(57))/6 ,x=(9-sqrt(57))/6

Find the zeros of 3x^2-9x+2=0

The zeros of 3x^2-9x+2=0 are x=(9+sqrt(57))/6 ,x=(9-sqrt(57))/6

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3 x^{2} - 9 x + 2 = 0

x = \frac{9 + 57}{6}, x = \frac{9 - 57}{6}

Decimal Notation

x = 2.75830 \dots, x = 0.24169 \dots

Solution steps

3 x^{2} - 9 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

(- 9)^{2} - 4 \cdot 3 \cdot 2 = 57

x_{1, 2} = \frac{- ( - 9 ) \pm 57}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 57}{2 \cdot 3}, x_{2} = \frac{- ( - 9 ) - 57}{2 \cdot 3}

x = \frac{- ( - 9 ) + 57}{2 \cdot 3} : \frac{9 + 57}{6}

x = \frac{- ( - 9 ) - 57}{2 \cdot 3} : \frac{9 - 57}{6}

The solutions to the quadratic equation are:

x = \frac{9 + 57}{6}, x = \frac{9 - 57}{6}

- 5 + 10

98 x^{3} y - 2 x y^{3}

(8 - g) (8 - g) = 0

512 - 193

(z + 1)^{2} = - 9

What are the solutions to the equation 3x^2-9x+2=0 ?
The solutions to the equation 3x^2-9x+2=0 are x=(9+sqrt(57))/6 ,x=(9-sqrt(57))/6
Find the zeros of 3x^2-9x+2=0
The zeros of 3x^2-9x+2=0 are x=(9+sqrt(57))/6 ,x=(9-sqrt(57))/6