What are the solutions to the equation 4x^2+x=-7x-3 ?

The solutions to the equation 4x^2+x=-7x-3 are x=-1/2 ,x=-3/2

Find the zeros of 4x^2+x=-7x-3

The zeros of 4x^2+x=-7x-3 are x=-1/2 ,x=-3/2

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4 x^{2} + x = - 7 x - 3

x = - \frac{1}{2}, x = - \frac{3}{2}

Decimal Notation

x = - 0.5, x = - 1.5

Solution steps

4 x^{2} + x = - 7 x - 3

Move

3

to the left side

4 x^{2} + x + 3 = - 7 x

Move

7 x

to the left side

4 x^{2} + 8 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

8^{2} - 4 \cdot 4 \cdot 3 = 4

x_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 8 + 4}{2 \cdot 4}, x_{2} = \frac{- 8 - 4}{2 \cdot 4}

x = \frac{- 8 + 4}{2 \cdot 4} : - \frac{1}{2}

x = \frac{- 8 - 4}{2 \cdot 4} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - \frac{3}{2}

(x - 2)^{\frac{7}{2}} - 4 (x - 2)^{\frac{3}{2}}

3 x + 6 = \frac{9 x - 3}{9}

5 x - 4 (4 - x) = x + 12

12 x + 12 = 13 x + 12

- 16 t^{2} + 150 + 20 = 0

What are the solutions to the equation 4x^2+x=-7x-3 ?
The solutions to the equation 4x^2+x=-7x-3 are x=-1/2 ,x=-3/2
Find the zeros of 4x^2+x=-7x-3
The zeros of 4x^2+x=-7x-3 are x=-1/2 ,x=-3/2