What are the solutions to the equation x^2+2x^1+1=0 ?

The solutions to the equation x^2+2x^1+1=0 are x=-1

Find the zeros of x^2+2x^1+1=0

The zeros of x^2+2x^1+1=0 are x=-1

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x^{2} + 2 x^{1} + 1 = 0

x = - 1

Solution steps

x^{2} + 2 x^{1} + 1 = 0

Refine

x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

x_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

x = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

x^{2} + 8 x = 9

- 3 z^{2} - 2 z + 4 = 0

5 + 4 x + (- 3) = - 10

- 5 \leq x < 2

\frac{x}{5} = 2 x - 6

What are the solutions to the equation x^2+2x^1+1=0 ?
The solutions to the equation x^2+2x^1+1=0 are x=-1
Find the zeros of x^2+2x^1+1=0
The zeros of x^2+2x^1+1=0 are x=-1