What are the solutions to the equation l(l-3)=238 ?

The solutions to the equation l(l-3)=238 are l=17,l=-14

Find the zeros of l(l-3)=238

The zeros of l(l-3)=238 are l=17,l=-14

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l (l - 3) = 238

l = 17, l = - 14

Solution steps

l (l - 3) = 238

Expand

l (l - 3) : l^{2} - 3 l

l^{2} - 3 l = 238

Move

238

to the left side

l^{2} - 3 l - 238 = 0

Solve with the quadratic formula

l_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 238 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 238) = 31

l_{1, 2} = \frac{- ( - 3 ) \pm 31}{2 \cdot 1}

Separate the solutions

l_{1} = \frac{- ( - 3 ) + 31}{2 \cdot 1}, l_{2} = \frac{- ( - 3 ) - 31}{2 \cdot 1}

l = \frac{- ( - 3 ) + 31}{2 \cdot 1} : 17

l = \frac{- ( - 3 ) - 31}{2 \cdot 1} : - 14

The solutions to the quadratic equation are:

l = 17, l = - 14

a^{2} + (- \frac{a}{7})^{2} = 1

a^{2} + \frac{10}{7} a + \frac{25}{49} = 0

420

3 k^{2} + 10 k + 7

lo g_{1} (2)

What are the solutions to the equation l(l-3)=238 ?
The solutions to the equation l(l-3)=238 are l=17,l=-14
Find the zeros of l(l-3)=238
The zeros of l(l-3)=238 are l=17,l=-14