What are the solutions to the equation 9x^2-48x+64=0 ?

The solutions to the equation 9x^2-48x+64=0 are x= 8/3

Find the zeros of 9x^2-48x+64=0

The zeros of 9x^2-48x+64=0 are x= 8/3

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9 x^{2} - 48 x + 64 = 0

x = \frac{8}{3}

Decimal Notation

x = 2.66666 \dots

Solution steps

9 x^{2} - 48 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 9 \cdot 64}{2 \cdot 9}

(- 48)^{2} - 4 \cdot 9 \cdot 64 = 0

x_{1, 2} = \frac{- ( - 48 ) \pm 0}{2 \cdot 9}

x = \frac{- ( - 48 )}{2 \cdot 9}

\frac{- ( - 48 )}{2 \cdot 9} = \frac{8}{3}

x = \frac{8}{3}

The solution to the quadratic equation is:

x = \frac{8}{3}

x^{2} + 2 x + 50 = 0

\frac{x - 10}{180} + \frac{1}{134} x + \frac{1}{100} x = 0

\frac{x}{2} - \frac{x}{6} = \frac{4}{3}

2 x - 5 = x - 1

\frac{5 + 4 i}{7 + 3 i}

What are the solutions to the equation 9x^2-48x+64=0 ?
The solutions to the equation 9x^2-48x+64=0 are x= 8/3
Find the zeros of 9x^2-48x+64=0
The zeros of 9x^2-48x+64=0 are x= 8/3