What are the solutions to the equation 9x^2-12x+5=0 ?

The solutions to the equation 9x^2-12x+5=0 are x= 2/3+i 1/3 ,x= 2/3-i 1/3

Find the zeros of 9x^2-12x+5=0

The zeros of 9x^2-12x+5=0 are x= 2/3+i 1/3 ,x= 2/3-i 1/3

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9 x^{2} - 12 x + 5 = 0

x = \frac{2}{3} + i \frac{1}{3}, x = \frac{2}{3} - i \frac{1}{3}

Solution steps

9 x^{2} - 12 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 9 \cdot 5}{2 \cdot 9}

Simplify

(- 12)^{2} - 4 \cdot 9 \cdot 5 : 6 i

x_{1, 2} = \frac{- ( - 12 ) \pm 6 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 i}{2 \cdot 9}, x_{2} = \frac{- ( - 12 ) - 6 i}{2 \cdot 9}

x = \frac{- ( - 12 ) + 6 i}{2 \cdot 9} : \frac{2}{3} + i \frac{1}{3}

x = \frac{- ( - 12 ) - 6 i}{2 \cdot 9} : \frac{2}{3} - i \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{2}{3} + i \frac{1}{3}, x = \frac{2}{3} - i \frac{1}{3}

\frac{s}{- 12} \leq - 5

(- 2)^{- 1}

9 x^{2} - 81 \leq 0

\frac{x}{2} \geq - 4

- 3 t^{2} + 20 t + 7 = 0

What are the solutions to the equation 9x^2-12x+5=0 ?
The solutions to the equation 9x^2-12x+5=0 are x= 2/3+i 1/3 ,x= 2/3-i 1/3
Find the zeros of 9x^2-12x+5=0
The zeros of 9x^2-12x+5=0 are x= 2/3+i 1/3 ,x= 2/3-i 1/3