What are the solutions to the equation -3t^2+20t+7=0 ?

The solutions to the equation -3t^2+20t+7=0 are t=-1/3 ,t=7

Find the zeros of -3t^2+20t+7=0

The zeros of -3t^2+20t+7=0 are t=-1/3 ,t=7

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- 3 t^{2} + 20 t + 7 = 0

t = - \frac{1}{3}, t = 7

Decimal Notation

t = - 0.33333 \dots, t = 7

Solution steps

- 3 t^{2} + 20 t + 7 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 3 ) \cdot 7}{2 ( - 3 )}

2 0^{2} - 4 (- 3) \cdot 7 = 22

t_{1, 2} = \frac{- 20 \pm 22}{2 ( - 3 )}

Separate the solutions

t_{1} = \frac{- 20 + 22}{2 ( - 3 )}, t_{2} = \frac{- 20 - 22}{2 ( - 3 )}

t = \frac{- 20 + 22}{2 ( - 3 )} : - \frac{1}{3}

t = \frac{- 20 - 22}{2 ( - 3 )} : 7

The solutions to the quadratic equation are:

t = - \frac{1}{3}, t = 7

5 x + 2 (x - 3) = - 2 (x - 1)

3 x^{2} - 2 (x + 5) = (x + 3)^{2} - 19

(\frac{5}{3} - \frac{2}{5}) \cdot \frac{7}{2} - \frac{1}{3}

4 t^{2} + 4 t + 1 = 0

x^{2} + 2 x \leq 0

What are the solutions to the equation -3t^2+20t+7=0 ?
The solutions to the equation -3t^2+20t+7=0 are t=-1/3 ,t=7
Find the zeros of -3t^2+20t+7=0
The zeros of -3t^2+20t+7=0 are t=-1/3 ,t=7