What are the solutions to the equation 4t^2+4t+1=0 ?

The solutions to the equation 4t^2+4t+1=0 are t=-1/2

Find the zeros of 4t^2+4t+1=0

The zeros of 4t^2+4t+1=0 are t=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 t^{2} + 4 t + 1 = 0

t = - \frac{1}{2}

Decimal Notation

t = - 0.5

Solution steps

4 t^{2} + 4 t + 1 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

t_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

t = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

t = - \frac{1}{2}

The solution to the quadratic equation is:

t = - \frac{1}{2}

x^{2} + 2 x \leq 0

8 y^{2} - 11 y + 3

\frac{1}{\frac{2 2}{3}}

x^{2} + 20 = 12 x

(3 x - 2) (x + 4) = 0

What are the solutions to the equation 4t^2+4t+1=0 ?
The solutions to the equation 4t^2+4t+1=0 are t=-1/2
Find the zeros of 4t^2+4t+1=0
The zeros of 4t^2+4t+1=0 are t=-1/2