What are the solutions to the equation x^2+20=12x ?

The solutions to the equation x^2+20=12x are x=10,x=2

Find the zeros of x^2+20=12x

The zeros of x^2+20=12x are x=10,x=2

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x^{2} + 20 = 12 x

x = 10, x = 2

Solution steps

x^{2} + 20 = 12 x

Move

12 x

to the left side

x^{2} + 20 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 12 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 20 = 8

x_{1, 2} = \frac{- ( - 12 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 8}{2 \cdot 1}

x = \frac{- ( - 12 ) + 8}{2 \cdot 1} : 10

x = \frac{- ( - 12 ) - 8}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 10, x = 2

(3 x - 2) (x + 4) = 0

- 8 (7 i - 3 i^{2})

\frac{14 !}{10 ! 4 !}

\frac{m ^{2} - 81}{m - 9}

(x - 5) (x + 1) < 0

What are the solutions to the equation x^2+20=12x ?
The solutions to the equation x^2+20=12x are x=10,x=2
Find the zeros of x^2+20=12x
The zeros of x^2+20=12x are x=10,x=2