What is (-5jk)/(35j^2k^2) ?

The solution to (-5jk)/(35j^2k^2) is -1/(7jk)

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simplify (-5jk)/(35j^2k^2)

simplify

\frac{- 5 jk}{35 j ^{2} k ^{2}}

- \frac{1}{7 jk}

Solution steps

\frac{- 5 jk}{35 j ^{2} k ^{2}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{5 jk}{35 j ^{2} k ^{2}}

Cancel the common factor:

5

= \frac{jk}{7 j ^{2} k ^{2}}

Cancel the common factor:

j

= \frac{k}{7 j k ^{2}}

Cancel the common factor:

k

= - \frac{1}{7 jk}

(7) (25) \cdot (1 - e^{- \frac{1}{1}})

\frac{28 x ^{3} y z ^{4}}{35 x y ^{4} z ^{2}}

\frac{( 2 π ( 1 ) )}{4} \cdot 3

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2 t^{2} - 24 t + 70 = 0