What is factor x^6-13x^4-52x^2+64 ?

The solution to factor x^6-13x^4-52x^2+64 is (x+1)(x-1)(x^2+4)(x+4)(x-4)

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factor x^6-13x^4-52x^2+64

factor

x^{6} - 13 x^{4} - 52 x^{2} + 64

(x + 1) (x - 1) (x^{2} + 4) (x + 4) (x - 4)

Solution steps

x^{6} - 13 x^{4} - 52 x^{2} + 64

Let

u = x^{2}

= u^{3} - 13 u^{2} - 52 u + 64

Factor

u^{3} - 13 u^{2} - 52 u + 64 : (u - 1) (u + 4) (u - 16)

= (u - 1) (u + 4) (u - 16)

Substitute back

u = x^{2}

= (x^{2} - 1) (x^{2} + 4) (x^{2} - 16)

Factor

x^{2} - 1 : (x + 1) (x - 1)

= (x + 1) (x - 1) (x^{2} + 4) (x^{2} - 16)

Factor

x^{2} - 16 : (x + 4) (x - 4)

= (x + 1) (x - 1) (x^{2} + 4) (x + 4) (x - 4)

83 \cdot 2

u^{\frac{5}{8}} \cdot u^{\frac{3}{4}}

(x - 1)^{2} - 25 = 0

- (- \frac{1}{4} x - 3) - 4 x = 7 (\frac{3}{4} x + 1) + 6

- \frac{4}{8}

What is factor x^6-13x^4-52x^2+64 ?
The solution to factor x^6-13x^4-52x^2+64 is (x+1)(x-1)(x^2+4)(x+4)(x-4)